linux线程锁使用实例,通过这个实例可迅速了解线程锁的使用方法。

  #include <pthread.h>
#include <stdio.h>
#include <sys/time.h>
#include <string.h>
#define MAX 20

pthread_t thread[2];
pthread_mutex_t mut;
int number=0, i;

void *thread2()
{


        printf ("thread2 : I'm thread 2/n");

        for (i = 0; i < MAX; i++)
        {

                printf("/tthread2 : number = %d/n",number);
                pthread_mutex_lock(&mut);
                        number++;
                pthread_mutex_unlock(&mut);
                sleep(1);
        }


        printf("thread2 :主函数在等我完成任务吗?/n");
        pthread_exit(NULL);
}

void *thread3()
{

        printf("thread3 : I'm thread 3/n");

        for (i = 0; i < MAX; i++)
        {

                printf("/tthread3 : number = %d/n",number);
                pthread_mutex_lock(&mut);
                        number++;
                pthread_mutex_unlock(&mut);
                sleep(2);
        }


        printf("thread3 :主函数在等我完成任务吗?/n");
        pthread_exit(NULL);
}

void thread_create(void)
{

        int temp;
        memset(&thread, 0, sizeof(thread));          //comment2
        /*创建线程*/
        if((temp = pthread_create(&thread[0], NULL, thread2, NULL)) != 0)       //comment3
                printf("线程2创建失败!/n");
        else
                printf("2被创建/n");

        if((temp = pthread_create(&thread[1], NULL, thread3, NULL)) != 0)  //comment3
                printf("3创建失败");
        else
                printf("3被创建/n");
}

void thread_wait(void)
{

        /*等待线程结束*/
        if(thread[0] !=0) {                   //comment4
                pthread_join(thread[0],NULL);
                printf("线程-----2已经结束/n");
        }
        if(thread[1] !=0) {                //comment5
                pthread_join(thread[1],NULL);
                printf("线程----3已经结束/n");
        }
}

int main()
{

        /*用默认属性初始化互斥锁*/
        pthread_mutex_init(&mut,NULL);

        printf("我是主函数哦,我正在创建线程,呵呵/n");
        thread_create();
        printf("我是主函数哦,我正在等待线程完成任务阿,呵呵/n");
        thread_wait();
        return 0;
}